JEE Mains XI: Physics, Chem, Math
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This quiz contains 5 questions
- 1
What is the mass percent of carbon in carbon dioxide (CO2)?
- A0.034%
- B27.27%
- C3.4%
- D28.7%
- 2
The empirical formula and molecular mass of a compound are CH2O and 180 respectively. What will be the molecular formula of the compound?
- AC9H18O9
- BCH2O
- CC6H12O6
- DC2H4O2
- 3
Which of the following options represents the correct limiting reagents in reactions (i), (ii) and (iii) respectively? (C = 12, O = 16, N = 14, P = 31) (i) C + O2 → CO2 (26g) (20g) (ii) N2 + 3H2 → 2NH3 (60g) (80g) (iii) P4 + 3O2 → P4O6 (100g) (200g)
- AC, N2, O2
- BC, N2, P4
- CO2, H2, P4
- DO2, N2, P4
- 4
If log10 2 = 0.301, log10 3 = 0.477, then the number of digits in the value of 312 × 28 is equal to
- A7
- B8
- C9
- D10
- 5
If x = log3 5, y = log17 25, which one of the following is correct:
- Ax < y
- Bx = y
- Cx > y
- DNone of these